1.

Cuprous chloride can not be prepared :

Answer»

by PASSING `SO_2` through the solution containing `CuSO_4` and NaCl
by HEATING EXCESS of copper with conc. HCL in presence of a LITTLE `KClO_3`
by boiling copper sulphate solution with excess of copper turnings in presence of hydrochloric acid
by dissolving cupric oxide or copper carbonate in conc. HCl

Solution :(D)`CuO+2HCl toCuCl_2+H_2O,Cu_2Cl_2` is not formed.
(A)`2CuSO_4 + 2NaCl+2H_2O+SO_2 to Cu_2Cl_2 + Na_2 SO_4 +2H_2SO_4`
(B)`Cu+HCl+[O]toCuCl_2+H_2O,CuCl_2+CutoCu_2Cl_2`
(C )`CuSO_4 + 2HCl to CuCl_2 +H_2SO_4 , CuCl_2 + Cu to Cu_2Cl_2`


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