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Current amplification factor of a common base configuration is 0.88. Find the value of base current when the emitter current is 1 mA. |
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Answer» SOLUTION :In a common-base arrangement, the CURRENT amplification FACTOR. `alpha=((DeltaI_(C))/(DeltaI_(E)))_(V_(CB))=(I_(C))/(I_(B))," Given "alpha=0.88, I_(E)=1mA` `therefore`Collector current `I_(C)=alphaI_(E)=0.88xx1=0.88mA`. Now since `I_(E)=I_(B)+I_(C)` `therefore` Base current `I_(B)=I_(E)-I_(C)=1-0.88=0.12mA`. |
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