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Current density in a copper wire is 2.5 xx 10^(8) Am^(-2). If 8A current if flowing through it diameter of the wire is ...... |
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Answer» 0.2 mm J = `(I)/(A) = (I)/(pi R^(2))` `thereforer =SQRT((I)/(pi J))` `= sqrt( (8)/(3.14 xx 2.5 xx 10^(8)) )` ` = sqrt( 1.009 xx 10^(-8) ) ` ` therefore r = 1 1.009 xx 10^(-4) ` m `therefore r = 1 xx 10^(-4)`m `therefore "Diameter " D = 2 xx 10^(-4 ) m = 2 xx 10^(-2)` CM = 0.02 cm = 0.2 mm |
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