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Current in a circuit falls from 5.0 A to 0.0 A in 0.1s. If an average emf of 200 V is induced give an estimate of the self-inductance of the circuit. |
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Answer» SOLUTION :`varepsilon=|L.(DI)/(dt)|,""varepsilon=200V,dI=(5-0)A,dt=0.1sec` `L=(EPSILON)/(((dI)/(dt)))=(200xx0.1)/(5)=4H` |
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