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Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit. |
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Answer» SOLUTION :Average self INDUCED emf is given by formula, `LT epsilon gt =-L ((DeltaI)/(Deltat))` `therefore 200=-L((0-5)/0.1)` `therefore` L=4H |
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