1.

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

Answer»

SOLUTION :Average self INDUCED emf is given by formula,
`LT epsilon gt =-L ((DeltaI)/(Deltat))`
`therefore 200=-L((0-5)/0.1)`
`therefore` L=4H


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