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| 1. |
Current in a circuit falls from 5A to 0A in 0.1s if an average emf of 200V is induced,determine the self inductance of the coil. |
| Answer» SOLUTION :dI=5-0=5A, dt=0.1s, `EPSILON`=200V, L=?, `epsilon =L(dI//dt`), `L=epsilondt//dI=200xx0.1//5=4H` | |