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Current in a coil falls from 5 A to 0 A in 0.1 s, calculate the induced emf in a coil if its self inductance is 4H. |
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Answer» Solution :When the current in the COIL falls from 5A to 0A in 0.15. The induced emf in a coil is , `E = L (DI)/(dt)` `E= 4xx (5)/(0.1) = 200V` |
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