1.

Current is passed through two cells connected in series,the first cell contains X(NO_3)_(3(aq)) and the second cell contains Y(NO_(3))_(2(aq)). The relative atomic masses of X and Y are in the ratio 1 : 2. What is the ratio of the liberated mass of X to that of Y?

Answer»

`3:2`
`1:2`
`1:3`
`3:1`

Solution :If atomic mass of X = a, then that of Y =2A
As EQ.wt. = Atomic mass/Valency
Eq. wt. of `X=a/3`, Eq. wt. of `Y=(2a)/2` =a
According to Faraday.s second LAW :
`"Liberated Mass of X"/"Liberated Mass of Y"="Eq. wt. of X"/"Eq. wt. of Y"=(a//3)/a=1/3`=1:3


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