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Current of 2A passing through a coil of 100 turns gives rise to a magnetic flux of 5 xx 10^(-3) Wb per turn. The magnetic energy associated will coil is ____ |
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Answer» `5xx10^(-3)` J `N phi = LI` `therefore L=(N phi)/I`…(1) The energy linked the coil `U=1/2LI^2` `therefore U=1/2 xx (Nphi)/I xx I^2` [ `because` from eqn. (1)] `therefore U=1/2 xx N PHII` `=1/2xx100xx5xx10^(-3)xx2` `therefore` U=0.5 J |
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