1.

Currents flowing in each of the following circuits A and B respectively are

Answer»

1 A, 2 A
2 A, 1 A
4 A, 2 A
2 A, 4 A

Solution :Circuit-A
The total resistance R is given by, `1/R = 1/4+1/4 = 2Omega`
According to ohm.s law, `V = I_(A)R`
`implies I_(A) = V/R = 8/2 = 4 A`
Circuit-B
`V = I_(B)R`
`implies I_(B) = V/R = 8/4 = 2 A`


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