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| 1. |
CuSO_(4).5H_(2)O is blue in colour while CuSO_(4) is colourless, why ? |
| Answer» Solution :In `CuSO_(4).5H_(2)O`, WATER acts as ligand as a result it causes crystal field SPLITTING. Hence d-d TRANSITION is possible in `CuSO_(4).5H_(2)O` and shows colour. In the anhydrous `CuSO_(4)` DUE to the ABSENCE of water (ligand), crystal field splitting is not possible and hence no colour. | |