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CuSO_(4) is colourless while CuSO_(4) 5H_(2)O is coloured. Why? [Ti(H_(2)O)_(6)]^(3+)is coloured while [Sc(H_(2)O)_(6)]^(3+) is colourless, why? |
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Answer» SOLUTION :`CuSO_(4)` does not have any ligand, so splitting of d-orbitals take place while `CuSO_(4), 5H_(2)O` has water as ligand. `TI^(3)` has one UNPAIRED electron while `SC^(3+)` does not have any unpaired `e^(-)`, hence no `d-d` transition in `SC^(3+)`. |
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