1.

CuSO_(4) when reacts with KCN forms CuCN which is insoluble in water. It is soluble in excess of KCN due to the formation of the complex.

Answer»

`K_(3)[CU(CN)_(4)]`
`K_(3)[Cu(CN)_(4))]`
`Cu(CN)_(2)`
`Cu[Kcu(CN)_(4)]`

SOLUTION :`CuSO_(4)` reacts with KCN to give a WHITE precipitate of cuprous cyanide and cyanogen gas. The cuprous cyanide DISSOLVES in excess of KCN forming `K_(3)[Cu(CN)_(4)]`
`CuSO_(4) + 2KCN to K_(2)SO_(4) + Cu(CN)_(2)`
`2Cu(CN)_(2) to 2CuCN + CN - CN`
`CuCN + 3KCN to K_(3)[Cu(CN)_(4)]`


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