1.

Cyclohexanol (I), acetic acid (II), 2,4,6-trinitrophenola(III) and phenol(IV) are given. In these the order of decreasing acidic character will be.

Answer»

`IIIgtIIgtIVgtI`
`IIgtIIIgtIgtIV`
`IIgtIIIgtIVgtI`
`IIIgtIVgtIIgtI`

Solution :
Explanation: presence of three `-NO_(2)` groups in o-, p- positions to pheonolic groups (in II) makes phenol strongly acidic because its correspoding CONJUGATE base is HIGHLY stabilised due to RESONANCE. ltbr. Conjugate base of `CH_(2)COOH, II i.e.,CH_(3)COO^(-)` is resonance hybrid of two equivalent structures. The conjugate base of phenol, IV is stabilised due to resonance (note that there all resonancing structures are not equivalent). The conjugate base of cyclohexanol, I does not exhibit resonance, hence not FORMED.


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