1.

Cyclopropane rearranges to form propene Delta to CH_(3) - CH = CH_(2) This follows first order kinetics . The rate constant is 2.714 xx 10^(-3) sec^(-1) . The initial concentration of cyclopropane is 0.29 M . What will be the concentration of cyclopropane after 100 sec .

Answer»

0.035 M
0.22 M
0.145 M
0.0018 M

Solution :`k = (2.303)/(t) "log" (a)/((a-x))`
(a-x) is the concentration LEFT after 100 sec .
`2.7 xx 10^(-3) = (2.303)/(100) "log" (0.29)/((a-x))`
`IMPLIES (a - x) = 0.22 M`.


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