1.

(D) 0.2 and 3.1 × 102365Calculate the weight of nitrogenpresent in 0.5 moles of NH(A) 8 g(C) 1 g3'(B) 9 g(D) 7 gClass IX -Chemist

Answer»

Nitrogen present in 1 mole ammonia =1 mole=14gSo nitrogen present in 0.5 mole ammonia =14g×0.5=7g



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