D7. In the adjoining figure, ABCD is a rectangle.If ZCEB: ZECB = 3:2,

1.	D7. In the adjoining figure, ABCD is a rectangle.If ZCEB: ZECB = 3:2, find(i) ZCEB(ii) ZDCFAEQues7
Answer» Answer: In *triangle* *CEB* , *ANGLE* B = 90° [ *ANGLE* OF *RECTANGLE* ] *ACC. TO ANGLE* *SUM* *PROPERTY* OF *TRIANGLE, angle* C + *angle* E + *angle* B = *180° angle* C + *angle* E + 90° = *180° angle* C + *angle* E = *180°- 90° angle* C + *angle* E = 90° (eq. *1st) LET* *angle* C *and* *angle* E be 2x *and* 3x *respectively* *putting* *value* of *angle* C *and* *angle* E in eq. *1st* 2x + 3x = 90° 5x = 90° x = 90/5 ° x = 18° *therefore* *angle* C = 2x = 2×18 = 36° *angle* E = 3x = 3×18 = 54° *follow* me *and* hit *the* *thanks BUTTON*

D7. In the adjoining figure, ABCD is a rectangle.If ZCEB: ZECB = 3:2, find(i) ZCEB(ii) ZDCFAEQues7

Answer»

Answer:

In triangle CEB ,

ANGLE B = 90° [ ANGLE OF RECTANGLE ]

ACC. TO ANGLE SUM PROPERTY OF TRIANGLE,

angle C + angle E + angle B = 180°

angle C + angle E + 90° = 180°

angle C + angle E = 180°- 90°

angle C + angle E = 90° (eq. 1st)

LET angle C and angle E be 2x and 3x respectively

putting value of angle C and angle E in eq. 1st

2x + 3x = 90°

5x = 90°

x = 90/5 °

x = 18°

therefore

angle C = 2x = 2×18 = 36°

angle E = 3x = 3×18 = 54°

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