D9. The HCF of two numbers is 23 and theirLCM is 1449. If one of the n

1.	D9. The HCF of two numbers is 23 and theirLCM is 1449. If one of the numbers is 161what is the other?(a
Answer» Solution : $\bf{\red{\underline{\bf{Given\::}}}}$ The H.C.F of TWO NUMBERS is 23 and their L.C.M is 1449.If one of the numbers is 161. $\bf{\red{\underline{\bf{To\:find\::}}}}$ The other number. $\bf{\red{\underline{\bf{Explanation\::}}}}$ Let the other number be r We KNOW that formula as; $\boxed{\bf{Product\:of\:two\:numbers=H.C.F.\times L.C.M.}}}}$ A/q $\longrightarrow\sf{161\times r=23\times 1449}\\\\\\\longrightarrow\sf{161r=33327}\\\\\\\longrightarrow\sf{r=\cancel{\dfrac{33327}{161} }}\\\\\\\longrightarrow\sf{\pink{r=207}}$ Thus; The other number will be r = 207 .

D9. The HCF of two numbers is 23 and theirLCM is 1449. If one of the numbers is 161what is the other?(a

Answer»

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The H.C.F of TWO NUMBERS is 23 and their L.C.M is 1449.If one of the numbers is 161.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The other number.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the other number be r

We KNOW that formula as;

$\boxed{\bf{Product\:of\:two\:numbers=H.C.F.\times L.C.M.}}}}$

A/q

$\longrightarrow\sf{161\times r=23\times 1449}\\\\\\\longrightarrow\sf{161r=33327}\\\\\\\longrightarrow\sf{r=\cancel{\dfrac{33327}{161} }}\\\\\\\longrightarrow\sf{\pink{r=207}}$

Thus;

The other number will be r = 207 .

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