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Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m , 10 m and 7 m respectively. From each can of paint 100 sq metre of area is painted. How many cans of paint will she need to paint the room ?Please give good answers only..____________✰No spams❌No copied answer❌Define in brief ✔️____________✰ |
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Answer» Step-by-step explanation: Question :- DANIEL is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m , 10 m and 7 m respectively. From each can of PAINT 100 sq METRE of area is painted. How many cans of paint will she need to paint the room ? Given :- Length of hall - 15m Breadth of hall - 10m Height of hall - 7m Area painted by 1 can = 100m^2 To Find :- Cans required to paint TH room? Formula Used :- L.S.A of Cuboid = 2h (l + b) Area of RECTANGLE = Length × Breadth Solution :- Area of wall to painted. Area of 4 walls + Area of top 2h(l + b) + (l × b) 2 h (15 + 10) + (15 × 10) 14 × 25 + 150 350 + 150 500m^2 No of cans required = Area of wall / Area of covered by 1 can 500 / 100 => 5 Hence, No of Cans required to paint the room is 5 cans. |
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