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Date: thetheFindreal parameter suchthatsolutionsequation (p-3) x² + (p²+0 x- 11p+8=0lengths of thelegsof the right trianglehy potaneous length 27.arewiththe |
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Answer» Let the length of the smallest leg be X. Then the length of the other leg is x+10 and the length of the hypotenuse is x+20. USING the Pythagorean theorem, we get,(x+20) 2 =x 2 +(x+10) 2 ⟹x 2 −20x−300=0solving this QUADRATIC EQUATION, we get, x=30. We discard the negative value.Thus the length of the hypotenuse is 50*this might not be the explanation to the exact question but it is similar so maybe it will help you* |
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