de Broglie (1924) predicted that small particles such as electrons should show wave -like properties along with paticle character. The wave length(lamda) associated with particle of mass m and moving with velocity v is given as lamda=h/(mv) where 'h' is plank's constant. The wave nature was confirmed by Davisson andGermer's experiment and modified equation for calculation of lamda can be given as: lamda=-h/(sqrt(2Em)) where E= kinetic energy of particle. lamda=h/(sqrt(2dVm)), where d= change of particle accelerated potnetial of V volt. The ratio of de-Broglie chi wavelength of molecules of H_(2) and He at 27^(@)C adn 127^(@)C respectively is

de Broglie (1924) predicted that small particles such as electrons sho

1.	de Broglie (1924) predicted that small particles such as electrons should show wave -like properties along with paticle character. The wave length(lamda) associated with particle of mass m and moving with velocity v is given as lamda=h/(mv) where 'h' is plank's constant. The wave nature was confirmed by Davisson andGermer's experiment and modified equation for calculation of lamda can be given as: lamda=-h/(sqrt(2Em)) where E= kinetic energy of particle. lamda=h/(sqrt(2dVm)), where d= change of particle accelerated potnetial of V volt. The ratio of de-Broglie chi wavelength of molecules of H_(2) and He at 27^(@)C adn 127^(@)C respectively is
Answer» 1.633 0.612 1.265 0.79 Solution :`LAMDA=h/(MV)` `lamda_(H_(1))=h/(m_(H_(2))sqrt((3RT_(1))/(mH_(2))))` `lamda_(H_(e))=h/(m_(H_(e))sqrt((3RT_(2))/(mH_(e))))` `(lamda_(H_(2)))/(lamda_(H_(2)))=sqrt((T_(2)xxm_(H_(e)))/(T_(xxm_(H_(2))))` `=sqrt((400xx4xx10^(-3))/(300xx2xx10^(-3)))` `=sqrt(8/3)` `=1.633` Hence a is the correct OPTION.