de Broglie (1924) predicted that small particles such as electrons should show wave -like properties along with paticle character. The wave length(lamda) associated with particle of mass m and moving with velocity v is given as lamda=h/(mv) where 'h' is plank's constant. The wave nature was confirmed by Davisson andGermer's experiment and modified equation for calculation of lamda can be given as: lamda=-h/(sqrt(2Em)) where E= kinetic energy of particle. lamda=h/(sqrt(2dVm)), where d= change of particle accelerated potnetial of V volt. If the kinetic energy of free electron is doubled,. Its de Broglie wavelengthh changes bythe

de Broglie (1924) predicted that small particles such as electrons sho

1.	de Broglie (1924) predicted that small particles such as electrons should show wave -like properties along with paticle character. The wave length(lamda) associated with particle of mass m and moving with velocity v is given as lamda=h/(mv) where 'h' is plank's constant. The wave nature was confirmed by Davisson andGermer's experiment and modified equation for calculation of lamda can be given as: lamda=-h/(sqrt(2Em)) where E= kinetic energy of particle. lamda=h/(sqrt(2dVm)), where d= change of particle accelerated potnetial of V volt. If the kinetic energy of free electron is doubled,. Its de Broglie wavelengthh changes bythe
Answer» `sqrt(2)` `1/(sqrt(2))` `2` `1/2` Solution :`K.E.=1/2 mv^(2)=E` `:.v=sqrt((2xxE)/m)` `:.(v_(2))/(v_(1))=sqrt(2)` Also `lamda_(1)=1/(mv_(1)),lamda_(2)=1/(mv_(2))` `(lamda_(2))/(lamda_(1))=(v_(1))/(v_(2))implieslamda_(2)=((v_(1))/(v_(2)))xxlamda_(1)=1/(sqrt(2))xxlamda_(1)` Hence B is the correct ANSWER.