de-Broglie wavelength associated with an electron accelerated through a potential difference V is lamda. What will be its wavelength when the accelerating potential is increased to 4 V?

de-Broglie wavelength associated with an electron accelerated through

1.	de-Broglie wavelength associated with an electron accelerated through a potential difference V is lamda. What will be its wavelength when the accelerating potential is increased to 4 V?
Answer» Solution :As `lamdaprop(1)/(sqrtV)`, HENCE on increasing accelerating POTENTIAL from V to 4V, de-Broglie WAVELENGTH decreases from `lamda` to `(lamda)/(2)`.

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de-Broglie wavelength associated with an electron accelerated through a potential difference V is lamda. What will be its wavelength when the accelerating potential is increased to 4 V?

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