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Decide giving reason which one of the following pairsexhibits the property indicated : (i) Sc^(3+) or Cr^(3+) exhibits paramagnetism(ii) Vor Mn exhibits more number of oxidation states ( Atomic numbers : Sc = 21, Cr= 24, V = 23 , Mn = 25) |
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Answer» Solution :(i)`. _(21) Sc = [ Ar] 3d^(1) 4S^(2) , Sc^(3+) = [Ar] -` No unparied electron `. _(24)Cr)=[Ar] 3d^(5)4s^(1) , Cr^(3+)= [Ar] 3d^(3) - `Three unpaired electron Hence, `Cr^(3+)` exhibits PARAMAGNETISM. (ii) Mn exhibits more number of oxidation states. Reason. `._(23) V = 3d^(3) 4s^(2)`. Its ox. states can be` + 2, + 3, +4, +5` `. _(25) Mn = 3d^(5) 4s^(2)` . Its ox. statescan be ` +2, +3,+4,+5,+6,+7` |
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