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Decinirmal solution of NaCI develop an osmotic pressur of 4.6 atosphers at 300 K. Calculate the degreedessociation,

Answer»


Solution :STEP I. Calculation os Van't Hoff factor (i)
`PI=("inRT")/Vori=(piV)/(nRT),pi=4.6 atm, n=0.1 N(or 0.1 M), T=300 K`
`V=1L, R=0.0821" L atm K"^(-1)mol^(-1)`
` i=((4.6" atm")xx(1L))/((0.1"mol"^(-1))xx(0.0821"L atm K"^(-1)mol^(-1))xx(300 K))=1.87`
`Step II. Calculation of degree of dissociation `(alpha)`
`Naoverset(("aq"))toNa^(+)(aq)THEREFORE" VALUE of "n=2`
`alpha=(i-1)/(n-1)or alpha=(1.87-1)/(2-1)=0.87xx100=87%.`


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