Saved Bookmarks
| 1. |
Deduce an expression for the electrostatic energy stored in a capacitance 'C' and having charge Q How will the electric field inside capacitor be affected when it is completely filled with a dielectric material of dielectric constant K ? |
|
Answer» Solution :The original electric FIELD inside capacitor `E = (sigma)/(in_(0)) = (Q)/(A in_(0))` On introducing dielectric new electric field `E. = (sigma)/(K in_(0)) = (Q)/(K A in_(0)) = (E)/(K)` Thus on introducing the dielectric , both energy stored and electric field are REDUCED by a factor . |
|