InterviewSolution
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InterviewSolution
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Deduce the expression for the electrostatic energy stored in a capacitor of capacitance C and having charge Q. How will the The electric field inside the capacitor be affected when it is completely filled with a dielectric meterial of dielectric constant k? |
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Answer» Solution :When the capacitor is filled COMPLETELY with a dielectric material of dielectric constant k, then capacitance BECOMES, C' = kC. Changed POTENTIAL difference, `V' = (Q)/(C')""[:. Q = " constant "]` `= (Q)/(kC)= (V)/(k)` Changed electric field, `E' = (V')/(d)= (V)/(kd)= (E)/(k)` The FINAL electric field will be `(1)/(k)` times of its previous value. |
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