Saved Bookmarks
| 1. |
Deficiency of how many electrons will produce a positive charge of 8xx10^(-19)C.? |
|
Answer» Solution :We know that `Q=+- "ne"` `rArr8xx10^(-19)=nxx1.6xx10^(-19)` `N=(8XX10^(-19))/(1.6xx10^(-19))=5` `THEREFORE`Dificiency of 5 electrons will produce `+8xx10^(19)C`. |
|