1.

Deficiency of how many electrons will produce a positive charge of 8xx10^(-19)C.?

Answer»

Solution :We know that `Q=+- "ne"`
`rArr8xx10^(-19)=nxx1.6xx10^(-19)`
`N=(8XX10^(-19))/(1.6xx10^(-19))=5`
`THEREFORE`Dificiency of 5 electrons will produce `+8xx10^(19)C`.


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