1.

Define an expression for the rate constant of a 1st order reaction. Define half life period. A first order reaction takes 69.3 minutes for 50% completion. How much time will be needed for 80% completion?

Answer»

SOLUTION :Given that `t_1/2=69.3`MIN.
`K=0.693/(69.3min)=10^-2min^-1`APPLYING the RELATION:`t=2.303/K"log"100/100-80)`
(for`80%` completion ,when` a =100,K=80) t=2.303/(10^-2S^-1"log5"=(230.3xx0.6989)`minute=160.96minutes:


Discussion

No Comment Found

Related InterviewSolutions