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Define electric field. Write its SI units. Write the magnitude and direction of electric field due to an electric dipole of length '2a' at the mid-point of the line joining the two charges. |
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Answer» Solution :Electric field at a point is defind as the ratio of force experienced by a small positive test charge PLACED at that point to the magnitude of test charge. Its SI units in `NC^(-1) ` We KNOW that electric field at a point on the equatorial line of a dipole is GIVEN by ` "" oversetto (E) =-(1)/(4 pi in _0) .(oversetto (p))/((a^(2) +r^(2))^(3//2)) ` At the mid-point of dipole r=0 and hence `oversetto E= (1)/(4 pi in _0).(oversetto p)/(a^(3)) ` Its direction is opposite to that of dipole moment ` oversetto p` |
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