InterviewSolution
| 1. |
Define enthalpy. What is the relation between ΔH and ΔE for a chemical reaction? Derive it. Write the enthalpy changes at constant volume and also at constant pressure? |
|
Answer» Enthalpy:- The heat content of a system at constant pressure is called enthalpy. Let a system undergo a change from state A to state B by absorbing q calories of heat from the surroundings at a constant pressure P. In such a case change of volume will take place. Let VA be the volume of the system in state A and VB is the volume of the system in state B. The work done by the system is given by equation. W = p(VB - VA) Substitute the value of W ΔE = q - p(VB - VA) ....(i) But ΔE = EB - EA ∴ EB - EA = q - p(VB - VA) ...(ii) or, EB - EA = q - pVB + pVA or, (EB + pVB) - (EA - pVA) = q ...(iii) The quantity E + pV is representing the total energy stored in a system and is called heat constant or enthalpy of a system. It is denoted by the symbol H ∴ H = E + pV ...(iv) E is definite quantity and is determined by the state of the system, p and V are also definite quantities. Therefore the quantity E + pV, i.e., H(enthalpy) is also a definite quantity and is determined by the state of the system. It is neither possible nor it is required to determine the absolute value of enthalpy of a system. Only the change in enthalpy of the system which takes place due to change in any of the variable of the system is required and can be measured accurately. For a system A, HA = EA + pVA ...(v) For a system B, HB = EB + pVB ...(vi) Subtracting (vi) from (v), HB - HA = (EB - EA) + p(VB - VA) ..(vii) ∴ ΔH = ΔE + PΔV ....(viii) ΔH represents the increase in that heat content of the system. Like ΔE it is also a definite property and depends on the initial and final state of the system. We can write Q = ΔE + pΔV Enthalpy changes at constant value. When the volume is kept constant ΔV = 0 pΔV = 0 ∴ ΔH = ΔE i.e., at constant volume the change in enthalpy is equal to the change in the internal energy. Enthalpy changes at constant pressure. For a change at constant pressure, the enthalpy change equals the heat absorbed by the substance. Since for a monoatomic gas, all the internal energy is accounted for by the kinetic energy of its molecules, we can estimate enthalpy H, per mole of such a gas at a temperature T as H = \(\frac{3}{2}\)RT + pV = \(\frac{3}{2}\)RT + RT = \(\frac{5}{2}\)RT [Since pV = RT] |
|