1.

Define "lowering of vapour pressure". Give equation for Raoult' s law of relative lowering of vapour pressure.

Answer»

Solution :DIFFERENCE between vapour pressure of a pure solvent and that of the solution.
OR
When a non-volatile solute is dissolved in a volatile solvent, va.pour pressure of the solution decreases.
`(P^(0) - P)/(P^(0)) = (n_(2))/(n_(1) + n_(2))`
OR
`(P^(0) - P)/(P^(0)) = X_(B)`
OR
`(P_(A)^(0) - P_(S))/(P_(A)^(0)) = (n_(2))/(n_(1) + n_(2))` .


Discussion

No Comment Found