1.

Define molality. 29.25 gms of NaCl are present in529.25 gms of solution . Find out the molality .

Answer»

SOLUTION :`MOLALITY (M) = W/"mol.wt" XX 1000 /(w"in"g)`
` = 29.25/58.5 xx 1000/(529.25 - 29.25) = 1`


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