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Define the distance of closest approach. An alpha-particle of kinetic energy K is bombarded on a thin gold foil. The distanceof the closest approach is r. What will bethe distance of closest approach for an alpah-particle of double the kinetic energy ? |
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Answer» SOLUTION :The distance of closest approach is the distance from thenucleuswhere total kineticenergy of `alpha` -particles is completely convertedinto POTENTIAL energy . The distance of closest approach, `R=(2Ze^2)/(4pi in_0K)` `therefore r prop 1/K` If the kinetic energy of the `alpha` -particle is doubled, then the distance of closest approach will become HALF. |
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