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Define the term rms value of a.c. Derive the relation between rms and peak value of a.c. |
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Answer» Solution :`THEREFORE I_(RMS)^(2) = 1/T int_(0)^(T) t^(2)dt = 1/T int_(0)^(T) I_(m)^(2) SIN^(2) omega t dt = I_(m)^(2)/(2T) int_(0)^(T) (1- cos 2 omega t) dt` `I_(m)^(2)/(2T) [(T-(0-0)/(2omega))] = I_(m)^(2)/2` `RARR I_(rms) = I_(m)/SQRT(2) = 0.707 I_(m)` |
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