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Define the term self inductance andwrite its S.I. unit. Obtain the expressioin for the mutual inductance of two long co-axial solenoids S_(1) and S_(2) wound one over the other, each of length L and radii n_(1) and r_(2) and n_(1) and n_(2) number of turns per unit lenght, when a current I is set up in the outer solenoids S_(2). |
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Answer» SOLUTION :Definitaioin of SELF inductance and its SI unit. Derivation of expression for mutual inductance. Self inductance of a coil equals,the magnitude of the magnetic flux, linked with it, when a unit current flows through it. Alternaively Self inductance, of a coil, equals the magnitude of the emf induced in it, when the current in the coil, is changing at a unit rate. SI unit: henry/ (webre/ampere)/(ohm second) When current `I_(2)` is passed through coil `S_(2)` it in TURNS set up a magnetic flux through `S_(1)=bar(omega)_(1)=(n_(1)l)(theta r_(1)^(2))(B_(2))` `bar(omega)_(1)=(n_(1)I)(pir_(1)^(2))(mu_(0)n_(2)I_(2))` `bar(omega)_(1)=mu_(0)n_(1)n_(2)I_(2)pir_(1)^(2)lI_(2)` But `bar(omega)_(1)=M_(12)I_(2)` `impliesM_(12)=mu_(0)n_(1)n_(2)pir_(1)^(2)l` |
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