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Define the term self inductance andwrite its S.I. unit. Obtain the expressioin for the mutual inductance of two long co-axial solenoids S_(1) and S_(2) wound one over the other, each of length L and radii n_(1) and r_(2) and n_(1) and n_(2) number of turns per unit lenght, when a current I is set up in the outer solenoids S_(2). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Definitaioin of <a href="https://interviewquestions.tuteehub.com/tag/self-1199734" style="font-weight:bold;" target="_blank" title="Click to know more about SELF">SELF</a> inductance and its SI unit. <br/> Derivation of expression for mutual inductance. <br/> Self inductance of a coil equals,the magnitude of the magnetic flux, linked with it, when a unit current flows through it. <br/> Alternaively <br/> Self inductance, of a coil, equals the magnitude of the emf induced in it, when the current in the coil, is changing at a unit rate. <br/> SI unit: henry/ (webre/ampere)/(ohm second)<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/DBT_SM_PHY_XII_EX_17_E01_027_S01.png" width="80%"/> <br/> When current `I_(2)` is passed through coil `S_(2)` it in <a href="https://interviewquestions.tuteehub.com/tag/turns-1429088" style="font-weight:bold;" target="_blank" title="Click to know more about TURNS">TURNS</a> set up a magnetic flux through <br/> `S_(1)=bar(omega)_(1)=(n_(1)l)(theta r_(1)^(2))(B_(2))` <br/> `bar(omega)_(1)=(n_(1)I)(pir_(1)^(2))(mu_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)n_(2)I_(2))` <br/> `bar(omega)_(1)=mu_(0)n_(1)n_(2)I_(2)pir_(1)^(2)lI_(2)` <br/> But `bar(omega)_(1)=M_(12)I_(2)` <br/> `impliesM_(12)=mu_(0)n_(1)n_(2)pir_(1)^(2)l`</body></html> | |