F = 5N

a = 8m/s²m = F/a = 5/8 kg

a2 = 24 m/s²m2 = 5/24 kg

m+m2 = 5/8 + 5/24 = (15+5)/24 = 20/24 = 5/6 kgacceleration of mass tied together = F/(m+m2) = 5/(5/6) = (5×6)/5 =6 m/s²

Suppose an object of mass, m is moving along a straight line with an initial velocity, u.It is uniformly accelerated to velocity, v in time, t by the application of a constant force, Fthroughout the time, t. The initial and final momentum of the object will be,p1 = mu and p2 = mv respectively. The change in momentum ∝ p2 – p1The change in momentum∝ mv – muThe change in momentum∝ m × (v – u).The rate of change of momentum ∝ m × (v −u)/tOr, the applied force,F ∝m × (v −u)/tF = km (v - u)/t

F = kma Here a [a = (v – u)/t ] is the acceleration, which is the rate of change of velocity. The quantity, k is a constant of proportionality.The SI units of mass and acceleration are kg and m s-2 respectively. The unit of force is so chosen that the value of the constant, k becomes one. For this, one unit of force isdefined as the amount that produces an acceleration of 1 m s-2 in an object of 1 kg mass.That is, 1 unit of force = k × (1 kg) × (1 m s-2).Thus, the value of k becomes 1. and F = ma which is the mathematical expression on the Newton's second law of motion.