1.

Degree of dissociation of 0.1 N CH_(3)COOH is (Dissociation constant = 1 xx 10^(-5))

Answer»

`10^(-5)`
`10^(-4)`
`10^(-3)`
`10^(-2)`

SOLUTION :Degree of dissociation `alpha = ?`
NORMALITY of solution `= 0.1 N = (1)/(10) N`
Dissociation constant `K = 1 xx 10^(-5)`
`K = C alpha^(2), alpha = sqrt((K)/(C)) = sqrt((1 xx 10^(-5))/(0.1)) , alpha = 1 xx 10^(-2)`.


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