InterviewSolution
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InterviewSolution
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`Delta H ` for the reaction `H-C-= N(g) + 2H_(2)(g) rarr H - underset(H) underset(|)overset(H ) overset(|)(C) - overset(H) overset(|)(N) - H (g)` is `- 150 kJ `. Calculate the bond energy of`C -= N`bond. [ Given bond energies of `C-H= 414 kJ mol^(-1), H-H= 435kJ mol^(-1), C-N = 293kJ mol^(-1), N-H =396 kJ mol^(-1)`] |
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Answer» Correct Answer - `893 kJ mol^(-1)` `Delta_(r)H^(@) = Sigma ` B.E. ( Reactants ) `-Sigma ` B.E. ( Produts) `- 150 = [ B.E. ( C-H) + B.E.(C-=N) + 2B.E.( H-H) ]-[3 xx B.E. (C-H) + B.E.(C-N) + 2 xx B.E. (N-H)]` |
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