1.

DeltaE^(@) of combustion of isobutylene is - X kJ mol^(-1). The value of DeltaH^(@) is

Answer»

`=DeltaE^(@)`
`GT DeltaE^(@)`
`=0`
`lt DeltaE^(@)`

SOLUTION :`(CH_(3))_(2)C=CH_(2)(G)+6O_(2)(g)rarr4CO_(2)(g)+4H_(2)O(l)`
`Deltan_(g)=4-6=-2` (i.e., NEGATIVE)
we know that `DeltaH=DeltaE+Deltan_(g)RT`
`=DeltaE-(Deltan_(g))RT (because Deltan_(g)=-ve)thereforeDeltaH lt DeltaE`.


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