`DeltaG^(@)` for `(1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3)` is `-16.5 kJ mol^(-1)` at `25^(@)C`. Find out `K_(p)` for the reaction. Also report `K_(p)` and `DeltaG^(@)` for: `N_(2)+3H_(2)hArr2NH_(3)` at `25^(@)C`

`DeltaG^(@)` for `(1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3)` is `-16.5 kJ mo

1.	`DeltaG^(@)` for `(1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3)` is `-16.5 kJ mol^(-1)` at `25^(@)C`. Find out `K_(p)` for the reaction. Also report `K_(p)` and `DeltaG^(@)` for: `N_(2)+3H_(2)hArr2NH_(3)` at `25^(@)C`
Answer» `-DeltaG^(@)=2.303RTlogK_(p)` `-(-16.5xx10^(3))=2.303xx8.314xx298 logK_(p)` `logK_(p)=(16500)/(2.303xx8.314xx298)` `:. K_(p)=779.41 atm^(-1)` Also , `K_(P_(1))` for `N_(2)+3H_(2)hArr2NH_(3)` `K_(p_(1))=(K_(p))^(2)=(779.41)^(2)` `K_(p_(1))=6.07xx10^(5)atm^(-2)` Also, `-DeltaG_(1)^(@)=2.303xx8.314xx298 log (6.07xx10^(5))J` `=32.998 kJ` `:. DeltaG_(1)^(@)=-32.998 kJ mol^(-1)`

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`DeltaG^(@)` for `(1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3)` is `-16.5 kJ mol^(-1)` at `25^(@)C`. Find out `K_(p)` for the reaction. Also report `K_(p)` and `DeltaG^(@)` for: `N_(2)+3H_(2)hArr2NH_(3)` at `25^(@)C`

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