1.

DeltaH_(f)^(@) " for "H_(2)O_(2) and H_(2)O are -188 kJ/mole and -286 kJ/mole. What will be the enthalpy change of the reaction 2H_(2)O_(2)(l)rarr2H_(2)O(l)+O_(2)(g)

Answer»

`-196` kJ/mole
`146 kJ//"mole"`
`-494 kJ//"mole"`
`-98 kJ//"mole"`

Solution :`H_(2)+O_(2)rarrH_(2)O_(2) ""DeltaH_(f)^(@)=-188 kJ//"mole...(i)"`
`H_(2)+(1)/(2)O_(2)rarrH_(2)O_(2)" " DeltaH_(f)^(@)=-286 kJ//"mole...(II)"`
eq. (i) - eq. (ii) `xx2` gives the required result.


Discussion

No Comment Found

Related InterviewSolutions