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`DeltaH` for `CaCO_(3)(s)rarrCaO(s)+CO_(2)(g)` is `176 kJ mol^(-1)` at `1240 K`. The `DeltaE` for the change is equal toA. `160KJ`B. `165.6KJ`C. `186.3KJ`D. `180.0KJ` |
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Answer» Correct Answer - A `Delta H = Delta E + Delta nRT` `:. Delta E = 176 - 1 xx 8.314xx8.314xx1240xx10^(-3)` `= 165.6 kJ` |
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