1.

DeltaU^(@) for combustion of methane is -X kJ mol^(-1). The value of DeltaH^(@) is

Answer»

`=DeltaU^(@)`
`gtDeltaU^(@)`
`LT DeltaU^(@)`
`=0`

Solution :`CH_(4)(g)+2O_(2)(g) to CO_(2)(g)+2H_(2)O(l)`
`Deltan_(g)=(n_(p)-n_(R))=1-3=-2`
`DeltaH^(@)=DeltaU^(@)+Deltan_(g)RT=-X-2RT`
Hence, `DeltaH^(@) lt Delta U^(@)`


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