Demonstrate that the binding energy of a nucleus with mass number A and charge Z can be found from Eq.(6.6b).

Demonstrate that the binding energy of a nucleus with mass number A an

1.	Demonstrate that the binding energy of a nucleus with mass number A and charge Z can be found from Eq.(6.6b).
Answer» Solution :From the BASIC formula `E_(b)=Z_(mH)+(A-Z)m_(n)-M` We define `Delta_(H)=m_(H)-1 am U` `Delta_(n)=m_(n)-1 am u` `Delta=M-A am u` Then clearly `E_(b)=Zdelta_(H)+(A-Z)Delta_(n)-Delta`

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Demonstrate that the binding energy of a nucleus with mass number A and charge Z can be found from Eq.(6.6b).

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