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Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:A. `1.14"mol kg"^(-1)`B. `3.28"mol kg"^(-1)`C. `2.28"mol kg"^(-1)`D. `0.44"mol kg"^(-1)` |
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Answer» Correct Answer - C `"Molality "(m)=(M)/(1000 " "d-MM_(1))xx100` `M="Molarity"," "M_(1)="Molecular mass"," "d="density"` `(2.05)/((1000xx1.02)-(2.05xx60))=1000` `=2.28mol" "kg^(-1)` |
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