1.

Density of 2M NaCI solution is 1.25 g/cc.The molality of the solution is :

Answer»

2.79 molal
0.279 molal
1.279 molal
3,85 molal

Solution :`"Mass of 3 M NaCI solution" = "density" x "volume" =(1.25g/ccxx1000cc)=1250g `
MOLAR mass of NaCI =58.5 G/mol
Mass of 3 moles of NaCI=`(58.5 g mol)XX(3 mol)=1.074 kg`
`"Molality of solution"=("No.of moles of NaCI")/("Mass of solvent in kg")`
`=((3mol))/((1.074 kg))=2.79 mol kg^(-1)=2.79 molal`


Discussion

No Comment Found

Related InterviewSolutions