1.

Density of a 2.05 M solution of acetic acid in water is 1.02 g/ml. The molarity of the solution is :

Answer»

3.28 mol `kg^(-1)`
2.28 mol `kg^(-1)`
0.44 mol `kg^(-1)`
2.14 mol `kg^(-1)`

SOLUTION :MASS of 1 L solution of 2.05 M ACETIC ACID
`=1.02xx1000=1020` G
Mass of solute in solution `=2.05xx60=123g`
Mass of solvent in solution
`=1020-123=897` g
Molality `=(2.05xx1000)/(897)=2.28 "mol kg"^(-1)`.


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