Derivaion of SECTION FORMULA .for 5 marks

1.	Derivaion of SECTION FORMULA .for 5 marks
Answer» Step-by-step explanation: Proof for Sectional Formula Let P(x_1, y_1) and Q(x_2, y_2) be two points in the xy – plane. Let M(x, y) be the point which divides line segment PQ INTERNALLY in the ratio m:N. PA, ~MN ~and~ QR are DRAWN perpendicular to x – axis. ... This is known as section formula.The formula can be derived by CONSTRUCTING two similar right triangles, as shown below. Their hypotenuses are along the line segment and are in the ratio m : n m:n m:n. P = ( x 1 + y 1 2 , x 2 + y 2 2 ) .

Answer»

Step-by-step explanation:

Proof for Sectional Formula

Let P(x_1, y_1) and Q(x_2, y_2) be two points in the xy – plane. Let M(x, y) be the point which divides line segment PQ INTERNALLY in the ratio m:N. PA, ~MN ~and~ QR are DRAWN perpendicular to x – axis. ... This is known as section formula.The formula can be derived by CONSTRUCTING two similar right triangles, as shown below. Their hypotenuses are along the line segment and are in the ratio m : n m:n m:n. P = ( x 1 + y 1 2 , x 2 + y 2 2 ) .

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